Question

If A and B be acute positive angles satisfying

$3 \sin 2 A - 2 \sin 2 B = 0$ then

• A.
• B.
• C.
• D.

Answer 1

Answer: (A)

Answer 2

From the given relations we have

Sin2B = $\left( \frac { 3 } { 2 } \right) \sin 2 \mathrm {~A}$

and

so that $\tan 2 \mathrm {~B} = \frac { \left( \frac { 3 } { 2 } \right) \sin 2 \mathrm {~A} } { 3 \sin ^ { 2 } \mathrm {~A} } = \cot \mathrm { A }$ or 1- tan2BtanA =0

⇒ A+2B = $\frac { \pi } { 2 }$ ⇒