If A and B are two mutually exclusive events, then P(A+B) is... | MATH - USE OF PERMUTATIONS AND COMBINATIONS IN PROBABILITY | SolveeIt | Solveeit

Today, August 18

Question

If A and B are two mutually exclusive events, then P(A+B) is equal to

A

P(1) P(B

B

P(1) + P(2)

C

P(1) P(B’) + P(A’) P(2)

D

P(1) P(B’) – P(A’) P(b

Answer

P(1) + P(2)

Explanation

Solution

Given A∩B = φ ⇒ P(A∩B) = 0

⇒ P(AUB) = P(1) + P(2) – P(A∩B) = P(1) + P(2).