Question
Question: If \( A \) and \( B \) are two mutually exclusive events, then the value of \( P\left( {A + B} \righ...
If A and B are two mutually exclusive events, then the value of P(A+B) is:
(A) P(A)+P(B)−P(AB)
(B) P(A)−P(B)
(C) P(A)+P(B)
(D) P(A)+P(B)+P(AB)
Solution
Hint : Here, P(x) denotes the probability of some event. Thus, P(AB) means the probability of AB , that is both the events A and B occur. We are given that the events A and B are mutually exclusive events. So, there is nothing common between the two events. Also, P(A+B) means the probability of A+B , that is either of the two events A and B occur. So, we will make use of the formula P(A+B)=P(A)+P(B)−P(AB) to solve the problem and find the value of P(A+B) .
Complete step-by-step answer :
In the given question, we have to find the probability that either of the two events A and B occur given that A and B are two mutually exclusive events. So, there is nothing common in the two events A and B and they cannot happen simultaneously.
Hence, the probability of the two events A and B happening together is zero.
Now, we will use the formula
P(A+B)=P(A)+P(B)−P(AB) to solve the problem and find the value of P(A+B) .
So, we get,
P(A+B)=P(A)+P(B)−P(AB)
We know that the probability of the two events A and B happening together is zero. So, we have, P(AB)=0 . Substituting this into the formula, we get,
⇒P(A+B)=P(A)+P(B)−0
Simplifying the calculations, we get,
⇒P(A+B)=P(A)+P(B)
So, we get the value of P(A+B) as P(A)+P(B) given that the two events A and B are mutually exclusive events.
So, option (C) is the correct answer.
So, the correct answer is “Option C”.
Note : These problems are the combinations of sets and probability, so, the concepts of both of the topics are used in these. Here the formula, P(A+B)=P(A)+P(B)−P(AB) is used. This formula is a restructured version of the formula of sets, which is, n(A∪B)=n(A)+n(B)−n(A∩B) where, n(x) denotes the number of elements in set x. This formula is modified into the formula of probability by dividing on both sides by n(U) , where U is the universal set.