Question

If A and B are two incidencies and P (A) = $\frac{3}{8} , P(B) = \frac{1}{2}, P(A \cap B) = \frac{1}{4}$ , then the value of $P(A' \cup B')$ is

• A. $\frac{3}{8}$
• B. $\frac{3}{4}$
• C. $\frac{1}{4}$
• D. $\frac{5}{8}$

Answer 1

Answer: (B)

$\frac{3}{4}$

Answer 2

$P (A' \cup B') = P ((A \cap B)') = 1 - P(A \cap B) = 1 - \frac{1}{4} = \frac{3}{4}$.