Solveeit Logo

Question

Question: If \(A\) and B are two events such that \(A\subseteq B\) , then \(P\left( {}^{B}/{}_{A} \right)\) ?...

If AA and B are two events such that ABA\subseteq B , then P(B/A)P\left( {}^{B}/{}_{A} \right) ?

Explanation

Solution

A set AA is a subset of another set BB if all elements of the set AA are elements of the set BB. So we can also describe that set AA is contained inside the set BB. Since set BBcontains elements which are not present in AA, we can say that AA is a proper subset of BB. But not the other way round. And in the question, we are given that AA is a subset of BB. So the probability of the intersection of the happening of AA and BB is the probability of happening of AA.

Complete step by step solution:
Since AA is a subset of BB, we can safely arrive at a conclusion with respect to their probabilities.
The conclusion is :
P(AB)=P(A)\Rightarrow P\left( A\cap B \right)=P\left( A \right)
In the question, we are asked about conditional probability.
Conditional probability is a measure of the probability of an event occurring, given that another event has already occurred.
We know the basic formula behind conditional probability. It is the following :
P(A/B)=P(AB)P(B)\Rightarrow P\left( {}^{A}/{}_{B} \right)=\dfrac{P\left( A\cap B \right)}{P\left( B \right)} .
Let us use this formula to solve our question.
P(B/A)=P(AB)P(A)\Rightarrow P\left( {}^{B}/{}_{A} \right)=\dfrac{P\left( A\cap B \right)}{P\left( A \right)}
Since it is specified in the question AA is a subset of BB,our conclusion was P(AB)=P(A)P\left( A\cap B \right)=P\left( A \right).
Let us substitute this and get the answer.
Upon substituting, we get the following :
P(B/A)=P(AB)P(A) P(B/A)=P(A)P(A) P(B/A)=1 \begin{aligned} & \Rightarrow P\left( {}^{B}/{}_{A} \right)=\dfrac{P\left( A\cap B \right)}{P\left( A \right)} \\\ & \Rightarrow P\left( {}^{B}/{}_{A} \right)=\dfrac{P\left( A \right)}{P\left( A \right)} \\\ & \Rightarrow P\left( {}^{B}/{}_{A} \right)=1 \\\ \end{aligned}

\therefore If AA and BBare two events such that ABA\subseteq B , then P(B/A)=1P\left( {}^{B}/{}_{A} \right)=1.

Note: It is very important to remember all the theorems in probability . We should be able to prove theorems such as the addition theorem, Bayes theorem. Problems from probability need a lot of practice. There is a lot of logic which is involved behind every problem. We should understand each and every step of the solution to be able to solve any kind of question from chapter. We should remember all the formulae and definitions as well.