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Question

Mathematics Question on Equations

If a and b are the roots of the equation x2 - 6x + 6=0, then the value of a2 + b2 is

A

36

B

24

C

12

D

6

Answer

24

Explanation

Solution

We have given the equation, x26x+6=0x^2 - 6x +6 = 0

So, the Sum of roots = a+b=6a + b = 6 – (i)

Product of roots = ab=6ab = 6

Squaring both sides in equation (i)

(a+b)2=(6)2(a + b)^2 = (6)^2

a2+b2+2ab=36a^2 + b^2 + 2ab = 36

(a2+b2)+2(6)=36(a^2 + b^2) + 2(6) = 36 as product of ab=36ab = 36

(a2+b2)=3612=24(a^2 + b^2) = 36 - 12 = 24

So, (a2+b2)=24(a^2 + b^2) = 24

The correct option is (B): 24