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Question

Mathematics Question on Probability

If AA and BB are mutually exclusive events, then

A

P(A)P(Bˉ)P\left(A\right)\le P\left(\bar{B}\right)

B

P(A)P(Bˉ)P\left(A\right)\ge P\left(\bar{B}\right)

C

P(A)<P(Bˉ)P\left(A\right) < P\left(\bar{B}\right)

D

None of these

Answer

P(A)P(Bˉ)P\left(A\right)\le P\left(\bar{B}\right)

Explanation

Solution

Since AA and BB are mutually exclusive events AB=ϕ\therefore A\cap B = \phi P(AB)=0 \Rightarrow P\left(A\cap B\right) = 0 P(AB)=P(A)+P(B)\Rightarrow P\left(A\cup B\right) = P\left(A\right)+P\left(B\right) P(A)+P(B)(P(AB)1) \Rightarrow P\left(A\right) +P\left(B\right)\le \left(\because P\left(A\cup B\right)\le1\right) P(A)1P(B) \Rightarrow P\left(A\right)\le 1-P\left(B\right) P(A)P(Bˉ) \Rightarrow P\left(A\right) \le P\left(\bar{B}\right)