Question
Mathematics Question on Differential Calculus
If a and b are fixed non-zero constants, then the derivative of x4a−x2b + cos x is ma + nb - p where
A
m = 4x3; n=x3−2; p = sinx
B
m=x5−4; n=x32; p = sinx
C
m=x5−4; n=x32; p = -sinx
D
m = 4x3; n=x32; p = -sinx
Answer
m=x5−4; n=x32; p = sinx
Explanation
Solution
The correct answer is () :