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Question: If A = 60<sup>0</sup>, a = 5, b =\(4\sqrt{3}\) in ∆ABC, then B =...

If A = 600, a = 5, b =434\sqrt{3} in ∆ABC, then B =

A

300

B

600

C

900

D

None of these

Answer

None of these

Explanation

Solution

sinBsinA\frac{\sin B}{\sin A} = ba\frac{b}{a}sinBsin60º\frac{\sin B}{\sin 60º} = 435\frac{4\sqrt{3}}{5}

⇒ sin B = 435×32\frac{4\sqrt{3}}{5} \times \frac{\sqrt{3}}{2}=65\frac{6}{5}