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Question: If a Î [–20, 0] than the graph of the function y = 16x<sup>2</sup> + 8 (a + 5) x – 7a – 5 is strictl...

If a Î [–20, 0] than the graph of the function y = 16x2 + 8 (a + 5) x – 7a – 5 is strictly above the x-axis. How many Integral values of ‘a’ are possible –

A

12

B

11

C

13

D

None of these

Answer

13

Explanation

Solution

y = 16x2 + 8(a + 5) x – 7a – 5 > 0 " x

for above x-axis y > 0

̃ 16x2 + 8(a + 5) x – 7a – 5 > 0 " x

\ D < 0

̃ 64 (a + 5)2 – 4.16(7a – 5) < 0

̃ a2 + 17a + 30 < 0

(a + 15) (a + 2) < 0

̃ –15 < a < –2.

Total Integral value of a is 13.