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Question: If A (2, – 1) and B(6, 5) are two points the ratio in which the foot of the perpendicular from (4, 1...

If A (2, – 1) and B(6, 5) are two points the ratio in which the foot of the perpendicular from (4, 1) to AB divides it, is-

A

8 :15

B

5 : 8

C

– 5 : 8

D

– 8 : 5

Answer

5 : 8

Explanation

Solution

Let, AmmB=λ1\frac { \mathrm { Am } } { \mathrm { mB } } = \frac { \lambda } { 1 }

\ m{6λ+1(2)λ+1,5λ+(1)λ+1}\mathrm { m } \left\{ \frac { 6 \lambda + 1 ( 2 ) } { \lambda + 1 } , \frac { 5 \lambda + ( - 1 ) } { \lambda + 1 } \right\} \ pm ⊥ AB

58\frac { 5 } { 8 }