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Question

Question: If \(A = 130{^\circ}\)and \(x = \sin A + \cos A,\) then...

If A=130A = 130{^\circ}and x=sinA+cosA,x = \sin A + \cos A, then

A

x>0x > 0

B

x<0x < 0

C

x=0x = 0

D

x0x \leq 0

Answer

x>0x > 0

Explanation

Solution

x=cos40+cos130=2cos85cos45>0x = \cos 40{^\circ} + \cos 130{^\circ} = 2\cos 85{^\circ}\cos 45{^\circ} > 0.