Solveeit Logo

Question

Question: If \({{a}_{1}},{{a}_{2}},{{a}_{3}},.....\) are positive numbers in GP then \[\log {{a}_{n}}\], \[\lo...

If a1,a2,a3,.....{{a}_{1}},{{a}_{2}},{{a}_{3}},..... are positive numbers in GP then logan\log {{a}_{n}}, logan+1\log {{a}_{n+1}} and logan+2\log {{a}_{n+2}} are in
(A) AP
(B) GP
(C) HP
(D) None of these

Explanation

Solution

We solve this problem by first going through the concept of Geometric progression. Then we use the formula b2=ac{{b}^{2}}=ac if a, b, c are in GP to find the relation between an,an+1{{a}_{n}},{{a}_{n+1}} and an+2{{a}_{n+2}}. Then we apply logarithm to the above equation and simplify it using the properties of logarithm like log(a×b)=loga+logb\log \left( a\times b \right)=\log a+\log b and logan=nloga\log {{a}^{n}}=n\log a. Then we see if they follow AP or HP or GP.

Complete step-by-step answer:
First let us go through the concept of GP.
A sequence of positive numbers are said to be in Geometric progression or GP if they have a common ratio.
Three numbers a, b, c are said to be in GP if b2=ac{{b}^{2}}=ac

We are given that a1,a2,a3,.....{{a}_{1}},{{a}_{2}},{{a}_{3}},..... are in GP.
Now let us consider the terms an,an+1{{a}_{n}},{{a}_{n+1}} and an+2{{a}_{n+2}}. As they are in GP, we can write them using the above formula as
an+12=an+2×ana_{n+1}^{2}={{a}_{n+2}}\times {{a}_{n}}
Now as we need the relation between logan\log {{a}_{n}}, logan+1\log {{a}_{n+1}} and logan+2\log {{a}_{n+2}}, let us apply logarithm to the above equation. By doing so we get,
logan+12=log(an+2×an)\log a_{n+1}^{2}=\log \left( {{a}_{n+2}}\times {{a}_{n}} \right)
Now let us consider a property of logarithms,
logan=nloga\log {{a}^{n}}=n\log a
Let us also consider another property of logarithms,
log(a×b)=loga+logb\log \left( a\times b \right)=\log a+\log b
Using these two properties we can simplify the above equation as,
2logan+1=logan+2+logan2\log {{a}_{n+1}}=\log {{a}_{n+2}}+\log {{a}_{n}}
We can write it as logan+1=logan+2+logan2\log {{a}_{n+1}}=\dfrac{\log {{a}_{n+2}}+\log {{a}_{n}}}{2}
Now let us consider the property of AP,
Three numbers a, b, c are said to be in AP if they satisfy the condition,
b=a+c2b=\dfrac{a+c}{2}
So, as we can see that our above equation is in the similar form as in the definition of AP, we can say that logan\log {{a}_{n}}, logan+1\log {{a}_{n+1}} and logan+2\log {{a}_{n+2}} are in AP.

So, the correct answer is “Option A”.

Note: The common mistake that is made by many people while solving this question is one might get confused between the AP, GP and HP. One might also make a mistake by taking the properties of logarithm wrong as logab=logalogb\log ab=\log a-\log b.