Question
Question: If \(92U^{238}\) undergoes successively 8 α-decays and 6 β-decays, then resulting nucleus is....
If 92U238 undergoes successively 8 α-decays and 6 β-decays, then resulting nucleus is.
A
82U206
B
82Pb206
C
82U210
D
82U214
Answer
82Pb206
Explanation
Solution
(Z=92)U(A=238)→(8α,6β)Z′⥂XA′
So A′=A−4nα= 238 – 4 × 8 = 206
and Z′=nβ−2nα+z = 6 – 2 × 8 + 92 = 82.