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Question

Question: If \(8C_{r} =^{8} ⥂ C_{r + 2}\), then the value of \(rC_{2}\) is....

If 8Cr=8Cr+28C_{r} =^{8} ⥂ C_{r + 2}, then the value of rC2rC_{2} is.

A

8

B

3

C

5

D

2

Answer

3

Explanation

Solution

8Cr=8Cr+28r=r+2r=38C_{r} =^{8} ⥂ C_{r + 2} \Rightarrow 8 - r = r + 2 \Rightarrow r = 3

Hence 3C2=33C_{2} = 3.