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Question

Mathematics Question on Differential equations

If 8x(9+x)dy=(4+9+x)1dx,x>08\sqrt{x}\left(\sqrt{9+\sqrt{x}}\right)dy = \left(\sqrt{4+\sqrt{9+\sqrt{x}}}\right)^{-1}\,\,dx, \,\,\,\,x > 0 and $

A

3

B

9

C

16

D

80

Answer

3

Explanation

Solution

dy=(18x(9+x)(4+9+x))dxdy =\left(\frac{1}{8 \sqrt{ x }(\sqrt{9+\sqrt{ x }})(\sqrt{4+\sqrt{9+\sqrt{ x }}})}\right) dx
Let 4+9+x=t4+\sqrt{9+\sqrt{x}}=t
129+x12xdx=dt\Rightarrow \frac{1}{2 \sqrt{9+\sqrt{x}}} \cdot \frac{1}{2 \sqrt{x}} d x=d t
dy=dt2t\Rightarrow d y=\frac{d t}{2 \sqrt{t}}
2dy=1tdt\Rightarrow 2 d y=\frac{1}{\sqrt{t}} d t
2y=2t+c2 y=2 \sqrt{t}+c
2y=24+9+x+c\Rightarrow 2 y=2 \sqrt{4+\sqrt{9+\sqrt{x}}}+c
y(0)=7y(0)=\sqrt{7}
c=0\Rightarrow c=0
y=4+9+xy=\sqrt{4+\sqrt{9+\sqrt{x}}}
y(256)=3y(256)=3