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Question: If 8 GM’s are inserted between 2 and 3, then the product of 8 GM’s is: A.6 B.36 C.216 D.1296...

If 8 GM’s are inserted between 2 and 3, then the product of 8 GM’s is:
A.6
B.36
C.216
D.1296

Explanation

Solution

If 8 GM’s are inserted between 2 and 3 (GM= geometric progression), then the first value is 2 and the last value is 3, then in geometric progression first value is denoted as aa and second value is denoted as arar, third value asar2a{r^2}, and so on, compare the values and find the value of aandra\,and\,r, which will help in finding out the value of product of 8GM’s.

Complete step-by-step answer:
If 8 GM’s are inserted between 2 and 3, then it looks like
2,GM1,GM2,GM3,GM4,GM5,GM6,GM7,GM8,32,\,G{M_1},\,G{M_2},\,G{M_3},\,G{M_4},\,G{M_5},\,G{M_6},\,G{M_7},\,G{M_8},\,3, and we know that geometric progression series is a,ar,ar2,ar3,ar4,............a,\,ar,\,a{r^2},\,a{r^3},\,a{r^4},............ compare the values with the series to figure out the values of a and r.
So, the value of a=2,ar=GM1,ar2=GM2,............,ar9=3a = 2,\,ar = G{M_1},\,a{r^2} = G{M_2},............,a{r^9} = 3
Now, we have ar9=3a{r^9} = 3 and a=2........(1)a = 2........\left( 1 \right),
ar9=3 r9=3a r9=32...........(2)  \Rightarrow a{r^9} = 3 \\\ \Rightarrow {r^9} = \dfrac{3}{a} \\\ \Rightarrow {r^9} = \dfrac{3}{2}...........\left( 2 \right) \\\
To find the value of product of 8GM’s, we have

GM1×GM2×........×GM8=ar×ar2×ar3×........×ar8 GM1×GM2×........×GM8=a8r8(8+1)2 GM1×GM2×........×GM8=a8r36 GM1×GM2×........×GM8=a8(r9)4 GM1×GM2×........×GM8=(2)8×(32)4 GM1×GM2×........×GM8=4×4×4×4×32×32×32×32 GM1×GM2×........×GM8=1296  \Rightarrow G{M_1} \times G{M_2} \times ........ \times G{M_8} = ar \times a{r^2} \times a{r^3} \times ........ \times a{r^8} \\\ \Rightarrow G{M_1} \times G{M_2} \times ........ \times G{M_8} = {a^8}{r^{\dfrac{{8\left( {8 + 1} \right)}}{2}}} \\\ \Rightarrow G{M_1} \times G{M_2} \times ........ \times G{M_8} = {a^8}{r^{36}} \\\ \Rightarrow G{M_1} \times G{M_2} \times ........ \times G{M_8} = {a^8}{\left( {{r^9}} \right)^4} \\\ \Rightarrow G{M_1} \times G{M_2} \times ........ \times G{M_8} = {\left( 2 \right)^8} \times {\left( {\dfrac{3}{2}} \right)^4} \\\ \Rightarrow G{M_1} \times G{M_2} \times ........ \times G{M_8} = 4 \times 4 \times 4 \times 4 \times \dfrac{3}{2} \times \dfrac{3}{2} \times \dfrac{3}{2} \times \dfrac{3}{2} \\\ \Rightarrow G{M_1} \times G{M_2} \times ........ \times G{M_8} = 1296 \\\

So, the product of 8GM’s is 1296.
Option D is correct.

Note: In geometric progression series, a is the first term and r is the common ratio between the numbers of the series. Don’t complicate the question by finding the values of each GM.