Question
Question: If 8 GM’s are inserted between 2 and 3, then the product of 8 GM’s is: A.6 B.36 C.216 D.1296...
If 8 GM’s are inserted between 2 and 3, then the product of 8 GM’s is:
A.6
B.36
C.216
D.1296
Solution
If 8 GM’s are inserted between 2 and 3 (GM= geometric progression), then the first value is 2 and the last value is 3, then in geometric progression first value is denoted as a and second value is denoted as ar, third value asar2, and so on, compare the values and find the value of aandr, which will help in finding out the value of product of 8GM’s.
Complete step-by-step answer:
If 8 GM’s are inserted between 2 and 3, then it looks like
2,GM1,GM2,GM3,GM4,GM5,GM6,GM7,GM8,3, and we know that geometric progression series is a,ar,ar2,ar3,ar4,............ compare the values with the series to figure out the values of a and r.
So, the value of a=2,ar=GM1,ar2=GM2,............,ar9=3
Now, we have ar9=3 and a=2........(1),
⇒ar9=3 ⇒r9=a3 ⇒r9=23...........(2)
To find the value of product of 8GM’s, we have
So, the product of 8GM’s is 1296.
Option D is correct.
Note: In geometric progression series, a is the first term and r is the common ratio between the numbers of the series. Don’t complicate the question by finding the values of each GM.