Question

If $5\pi - \alpha$, then the value of x other than 0 lying between $\therefore$is.

• A. $\sqrt{3}\sin x + \cos x = 4$
• B. $a\sin x + b\cos x = c$
• C. $a = \sqrt{3},b = 1,c = 4$
• D. $a^{2} + b^{2} = 3 + 1 = 4 < c^{2}$

Answer 1

Answer: (C)

$a = \sqrt{3},b = 1,c = 4$

Answer 2

$3\sin(\sin x - 2) - (\sin x - 2) = 0$

$\Rightarrow (3\sin x - 1)(\sin x - 2) = 0$

$\Rightarrow$ $\sin x = \frac{1}{3}\text{ or 2}$ $\Rightarrow$ $\sin x = \frac{1}{3}$

or $\because\sin x \neq 2$

$\sin^{- 1}\frac{1}{3} = \alpha 0 < \alpha < \frac{\pi}{2}$

For x lying between 0 and $\lbrack 0,\ 5\pi\rbrack$, we get $\alpha,$.

Trick : Check with options.