Question

If 50 Vernier divisions are equal to 49 main scale divisions of a travelling microscope and one smallest reading of the main scale is 0.5 mm, the Vernier constant of the travelling microscope is:

• A. 0.01 mm
• B. 0.1 mm
• C. 0.1 cm
• D. 0.01 cm

Answer 1

Answer: (A)

0.01 mm

Answer 2

The Vernier constant (VC) is calculated as:

$\text{VC} = \text{Value of 1 MSD} - \text{Value of 1 VSD}$

Given that 50 Vernier divisions correspond to 49 main scale divisions:

- The value of 1 MSD is 0.5 mm.
- Therefore, the value of 1 VSD is:

$\text{Value of 1 VSD} = \frac{49 \times 0.5 \text{ mm}}{50} = 0.49 \text{ mm}$

Calculating the VC:

$\text{VC} = 0.5 \text{ mm} - 0.49 \text{ mm} = 0.01 \text{ mm}$