Question

If 5 coins are tossed simultaneously. Then probability of getting atleast one head is

• A. 1/32
• B. 31/32
• C. 3/32
• D. 5/32

Answer 1

Answer: (B)

31/32

Answer 2

N(S) = 2⁵

Let E be the event of getting atleast one head.

Then $\overline { \mathrm { E } }$ is the event of getting all tails.

∴ = 1

= $\frac { 1 } { 25 } = \frac { 1 } { 32 }$

P(5) = 1 - $\frac { 1 } { 32 } = \frac { 31 } { 32 }$.