Question

If $4x + 3 < 6x + 7$, then $x\in$

• A. ($2$, $\infty$)
• B. ($-2$, $\infty$)
• C. ( $-\infty$, $2$)
• D. ($-\infty$, $\infty$)

Answer 1

Answer: (B)

($-2$, $\infty$)

Answer 2

We have, $4x + 3 < 6x + 7$. or $4x - 6x < 7 - 3$ or $-2x < 4$ or $x > \- 2$ i.e., all real numbers which are greater than $-2$, are solutions of the given inequality. Hence, the solution set is ($-2$, $\infty$).