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Question: If \( 400\Omega \) of resistance is made by adding four \( 100\Omega \) resistance of tolerance \( 5...

If 400Ω400\Omega of resistance is made by adding four 100Ω100\Omega resistance of tolerance 5%5\% , then the tolerance of the combination is:
(A) 20%20\%
(B) 5%5\%
(C) 10%10\%
(D) 15%15\%

Explanation

Solution

The maximum difference between its actual value and the required value is the tolerance of a resistor and is generally expressed as a percentage plus or minus value. Tolerance is the proportion of error in the resistance of the resistor, or how much more or less you can expect from its stated resistance to be the actual measured resistance of a resistor.

Formula Used The formula to find out the total tolerance is given by
T=ΔRRT = \dfrac{{\Delta R}}{R}
Where, TT is the total tolerance
ΔR\Delta R is the tolerance percentage
RR is the resistance of the resistor.

Complete step by step answer:
Let each of the four resistances be R1{R_1} , R2{R_2} , R3{R_3} , and R4{R_4}
It is also given that the tolerance of each resistor is 5%5\%
That is
ΔR1R=5100\dfrac{{\Delta {R_1}}}{R} = \dfrac{5}{{100}}
So, we get
ΔR1=100×5100=5Ω\Delta {R_1} = 100 \times \dfrac{5}{{100}} = 5\Omega
It is also provided in the question that
R1=R2=R3=R4{R_1} = {R_2} = {R_3} = {R_4}
Therefore,
ΔR1=ΔR2=ΔR3=ΔR4=5Ω\Delta {R_1} = \Delta {R_2} = \Delta {R_3} = \Delta {R_4} = 5\Omega
Let the net effective resistance be Re{R_e}
Then,
Re=R1+R2+R3+R4{R_e} = {R_1} + {R_2} + {R_3} + {R_4}
Re=100+100+100+100=400Ω\Rightarrow {R_e} = 100 + 100 + 100 + 100 = 400\Omega
Now if we apply differential sign on both the sides of the equation, we get
ΔRe=ΔR1+ΔR2+ΔR3+ΔR4\Delta {R_e} = \Delta {R_1} + \Delta {R_2} + \Delta {R_3} + \Delta {R_4}
Now we will put the value of each term in the given equation
ΔRe=5+5+5+5=20Ω\Delta {R_e} = 5 + 5 + 5 + 5 = 20\Omega
And we have to find out the total tolerance of the combination of resistances
That is, we need to find
ΔReRe×100\dfrac{{\Delta {R_e}}}{{{R_e}}} \times 100
Now let us put values of each term
20400×100=5%\dfrac{{20}}{{400}} \times 100 = 5\%
Hence the correct option is (B.)

Note:
In an electrical circuit, resistance is a measure of the opposition to current flow. We measure resistance in ohms. Tolerance on the other hand is measured in percentage. It can either be positive or negative.