Question

If 4 moles of an ideal gas at 300 K occupy volume of $89.6L$then pressure of the gas will be

• A. 2 atm
• B. 1 atm
• C. $1.099atm$
• D. $2.910atm$

Answer 1

Answer: (C)

$1.099atm$

Answer 2

: PV = nRT

$P = \frac{4 \times 0.0821 \times 300}{89.6} = 1.099$atm