Question

If $(4)^{\log_9 3} + (9)^{\log_2 4} = (10)^{\log_x 83}$, then X is equal to

• A. 10
• B. 4
• C. -10
• D. -4

Answer 1

Answer: (A)

10

Answer 2

\left(4\right)^{\log _{_{3^2^{^3}}}} + \left(9\right)^{\log _{_{2^{2^2}}}} = \left(10\right)^{\log _{x}}^{ 83}
$\Rightarrow \left(4\right)^{12} + 9^{2} = \left(10\right)^{\log _{x} 83}$
[Using $x 0\log_a y = y \, log_a x$]
$\Rightarrow \left(83\right)^{1} = \left(83\right)^{\log _{x} 10} \Rightarrow 1 =\log_{x} 10 \Rightarrow x = 10$