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Question

Question: If 4 cos A cos B + sin 2A + sin 2B + sin 2C = 4 then ∆ABC is...

If 4 cos A cos B + sin 2A + sin 2B + sin 2C = 4 then ∆ABC is

A

Right angle

B

Isosceles

C

Right angled isosceles

D

None of these

Answer

Right angled isosceles

Explanation

Solution

Q 4 cos A cos B + 4 sin A sin B sin C = 4

sin C = 1cosAcosBsinAsinB\frac{1 - \cos A\cos B}{\sin A\sin B}≤ 1 ... (1)

⇒ cos (A – B) ≥ 1

⇒ cos (A – B) = 1

True if A = B … (2)

Put (2) in (1)

sin C = 1

C = 900