Question
Question: If 4 cos A cos B + sin 2A + sin 2B + sin 2C = 4 then ∆ABC is...
If 4 cos A cos B + sin 2A + sin 2B + sin 2C = 4 then ∆ABC is
A
Right angle
B
Isosceles
C
Right angled isosceles
D
None of these
Answer
Right angled isosceles
Explanation
Solution
Q 4 cos A cos B + 4 sin A sin B sin C = 4
sin C = sinAsinB1−cosAcosB≤ 1 ... (1)
⇒ cos (A – B) ≥ 1
⇒ cos (A – B) = 1
True if A = B … (2)
Put (2) in (1)
sin C = 1
C = 900