If 4(4b-3a) = 2(2b+c) = 8(c-a) and a + b + c = 11, then find... | Quantitative Aptitude | SolveeIt | Solveeit

Today, August 24

Question

If 4(4b-3a) = 2(2b+c) = 8(c-a) and a + b + c = 11, then find the value of $4(\frac{1}{ab}+\frac{1}{bc}+\frac{1}{ca})$

A

$\frac{11}{9}$

B

$\frac{9}{11}$

C

$\frac{6}{5}$

D

$\frac{5}{6}$

Answer

$\frac{11}{9}$

Explanation

Solution

The correct option is (A): $\frac{11}{9}$