Question

If 3x + i(4x-y) = 6-i, where x and y are real numbers, then the value of x and y are respectively

• A. 3,9
• B. 2,9
• C. 2,4
• D. 3,4

Answer 1

Answer: (B)

2,9

Answer 2

To find the values of x and y in the equation $3x + i(4x - y) = 6 - i$, we can equate the real and imaginary parts on both sides of the equation.
Equating the real parts:
3x = 6
Dividing both sides by 3, we get:
x = 2
Equating the imaginary parts:
$i(4x - y) = -i$
Multiplying both sides by -i, we get:
$4x - y = -1$
Substituting the value of x from the first equation, we have:
$4(2) - y = -1$
$8 - y = -1$
Subtracting 8 from both sides, we get:
$-y = -9$
Dividing both sides by -1, we get:
y = 9
Therefore, the values of x and y in the equation $3x + i(4x - y) = 6 - i$ are x = 2 and y = 9 (option B).