Question

If $(3x - 1) = (Ax + B)(x + 2) + C(x^{2} - x + 1)$ then x be.

• A. 2
• B. 3
• C. 3.5
• D. $2A + B - C = 3$

Answer 1

Answer: (A)

2

Answer 2

$x + 10 = 36 + x - 2 - 12\sqrt{x - 2}$

$\Rightarrow 2 = \sqrt{x - 2} \Rightarrow$ $4 = x - 2$

$\Rightarrow$

$x = - 6\therefore x = 6$; $\frac{\sqrt{6 + 2\sqrt{3} + 2\sqrt{2} + 2\sqrt{6}} - 1}{\sqrt{5 + 2\sqrt{6}}}$ $\frac{(1 + \sqrt{2} + \sqrt{3}) - 1}{(\sqrt{3} + \sqrt{2})}$

i.e., $\frac{\sqrt{3} + \sqrt{2}}{\sqrt{3} + \sqrt{2}} = 1$; $2x + 3 = a(x - 3) + b(x + 1)$ x will be 2.