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Question

Question: If 3 gm of glucose (mol. wt. 180) is dissolved in 60 gm of water at \(15 ^ { \circ } \mathrm { C }\...

If 3 gm of glucose (mol. wt. 180) is dissolved in 60 gm of water at 15C15 ^ { \circ } \mathrm { C } . Then the osmotic pressure of this solution will be.

A

0.34 atm

B

0.65 atm

C

6.57 atm

D

5.57 atm

Answer

6.57 atm

Explanation

Solution

π=CRT=3×1000180×60×0.0821×288\pi = C R T = \frac { 3 \times 1000 } { 180 \times 60 } \times 0.0821 \times 288 =6.56 atm= 6.56 \mathrm {~atm} .