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Question: If \(3 + \frac { 1 } { 4 }\) (3 + d) + \(\frac { 1 } { 4 ^ { 2 } }\) (3 + 2d)+….upto ¥ = 8, then ...

If 3+143 + \frac { 1 } { 4 } (3 + d) + 142\frac { 1 } { 4 ^ { 2 } } (3 + 2d)+….upto ¥ = 8, then the value of d is

A

9

B

5

C

1

D

None of these

Answer

9

Explanation

Solution

Do your self ¥ A. G. P