if (2x^y+3y^x=20) then (\frac{dy}{dx}) at (2,2) is equal to:... | Mathematics | SolveeIt | Solveeit

Today, August 19

Question

if $2x^y+3y^x=20$ then $\frac{dy}{dx}$ at (2,2) is equal to:

A

$-(\frac{3+log_e4}{ 2+loge_8})$

B

$-(\frac{3+log_e16}{ 4+loge_8})$

C

$-(\frac{3+log_e8}{ 2+loge_4 })$

D

$-(\frac{2+log_e8}{ 3+loge_4})$

Answer

$-(\frac{2+log_e8}{ 3+loge_4})$

Explanation

Solution

The correct option is(D): $-(\frac{2+log_e8}{ 3+loge_4})$