Question
Question: : If \[2x = 3 + 5i\], then the value of \[2{x^3} + 2{x^2} - 7x + 72\] is 1 \[4\] 2 \[ - 4\] 3 ...
: If 2x=3+5i, then the value of 2x3+2x2−7x+72 is
1 4
2 −4
3 8
4 −8
Solution
To find the value of 2x3+2x2−7x+72, we need to find the value of x from the given expression 2x=3+5i, then from the obtained value of x; find x2 and x3 respectively. Then substitute the obtained value of x, x2 and x3 in the given expression 2x3+2x2−7x+72.
Complete step by step answer:
Let us write the given data:
2x=3+5i
In which the equation can be written in terms of xas:
x=23+5i
Then with respect to x, x3 becomes
x3=(23+5i)3
Expanding the cube root terms, we get:
⇒x3=(827+135i−225−125i)
⇒x3=8(−198+10i)
And now to obtain the value of x2, we have:
⇒x2=4(9−25+30i)
⇒x2=4(−16+30i)
Hence, to find the value of 2x3+2x2−7x+72, we need to substitute all the obtained values of x, x2andx3i.e.,
2x3+2x2−7x+72=28(−198+10i)+24(−16+30i)−72(3+5i)+72
Evaluate each term, as:
=(2−99−8−221+72)+[(410+15)2−35]i
Simplifying the terms, we have:
=(2−99−16−21+144)+(410+60−70)i
Evaluating the numerator terms, we get:
=(28)+(40)i
=28
Hence, we get:
=4
∴2x3+2x2−7x+72=4
So, the correct answer is “Option 1”.
Note: The key point to note is that, the given expression is not quadratic hence, while finding the value of x from the given expression we must also find the value of x, such that find x2 and x3 we need to substitute in the given asked expression.