Question

If $2\sqrt{10}$, then $x^{2} + px + q = 0$

• A. {3, 4}
• B. {3, –3}
• C. {3, 4, –3, –4}
• D. {–3, –3}

Answer 1

Answer: (C)

{3, 4, –3, –4}

Answer 2

$\mathbf{a < -2}$ and $x^2 - 2ax + a^2 + a - 3 = 0$

⇒ $a < 2$

⇒ $2 \leq a \leq 3$, ⇒ $3 < a \leq 4$, and $a > 4$

⇒ $x$ and $x^2 - 6x + 10$.