Solveeit Logo
Login

Question

Question: If \((2\sin\theta + 1)(\sin\theta - 2) = 0\), then the general value of\(\Rightarrow\)is....

If (2sin⁡θ+1)(sin⁡θ−2)=0(2\sin\theta + 1)(\sin\theta - 2) = 0, then the general value of⇒\Rightarrowis.

A

sin⁡θ=−12\sin\theta = - \frac{1}{2}

B

∵sin⁡θ≠2)\because\sin\theta \neq 2)

C

⇒\Rightarrow

D

None of thes

Answer

sin⁡θ=−12\sin\theta = - \frac{1}{2}

Explanation

Solution

⇒\Rightarrow ⇒ tan⁡2θ=13=tan⁡2(π6)⇒θ=nπ±π6\tan^{2}\theta = \frac{1}{3} = \tan^{2}\left( \frac{\pi}{6} \right) \Rightarrow \theta = n\pi \pm \frac{\pi}{6}

⇒\Rightarrow sin⁡4θ=2sin⁡(4θ)sin⁡(3θ)\sin 4\theta = 2\sin(4\theta)\sin(3\theta).