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Question

Mathematics Question on Inverse Trigonometric Functions

If 2sin−1x−3cos−1x=4,x∈[−1,1]2sin^{-1}x -3 cos^{-1}x =4, x∈ [-1,1] then 2sin−1x+3cos−1x2sin^{-1}x +3cos^{-1}x is equal to

A

4−6π5\frac{4-6{\pi}}{5}

B

6π−45\frac{6{\pi}-4}{5}

C

3π2\frac{3\pi}{2}

D

0

Answer

6π−45\frac{6{\pi}-4}{5}

Explanation

Solution

The correct answer is Option (B) : 6π−45\frac{6{\pi}-4}{5}