Question
Question: If \(2i\) then \(- 2i\)...
If 2i then −2i
A
−2
B
2
C
i582+i580+i578+i576+i574i592+i590+i588+i586+i584−1=
D
(2, 1)
Answer
−2
Explanation
Solution
(1−i)x+(1+i)y=1−3i in+in+1+in+2+in+3=in[1+i+i2+i3] =in[1+i−1−i]=0
Equating real and imaginary parts, we get ∵(1+i)2=1+i2+2i=2iand (1−i)2=1+i2−2i=−2i; ⇒(1+i)8+(1−i)8=(2i)4+(−2i)4 =24(i4+i4). Thus point is =25=32..