Question

If $2i$ and $\alpha - i\beta(\alpha,\beta\text{real}),$ , then $\left( \frac{3 - 4ix}{3 + 4ix} \right) =$

• A. $x$
• B. $y$
• C. $(x + iy)$
• D. None of these

Answer 1

Answer: (A)

$x$

Answer 2

$z^{4} = - 117 - 44i$

$= \frac { ( 1 + a - c + i b ) ( 1 + a + c + i b ) } { ( 1 + a + c ) ^ { 2 } + b ^ { 2 } }$ $z^{4} - 3z^{3} + 3z^{2} + 99z - 95 = 5$

= $z = 3 - 4i$

$(z - 3)^{2} = - 16$.