Question

If 20VSD coincide with 19MSD and 1MSD is 0.5mm, then the vernier constant is –

• A. 0.0025cm
• B. 0.025cm
• C. 0.25cm
• D. None

Answer 1

Answer: (A)

0.0025cm

Answer 2

L.C. = $\frac { 1 \mathrm { MSD } } { \mathrm { n } } = \frac { 1 \times 0.5 \times 10 ^ { - 1 } } { 20 }$ = 0.0025 cm