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Question: If 20\(P = 1.0atm,T = 500K\) gas at 1 atm. is expanded to 50 \(- 80^{o}C\) at constant T, then what ...

If 20P=1.0atm,T=500KP = 1.0atm,T = 500K gas at 1 atm. is expanded to 50 −80oC- 80^{o}C at constant T, then what is the final pressure.

A

CpC_{p}

B

CvC_{v}

C

6.02×10236.02 \times 10^{23}

D

None of these

Answer

CpC_{p}

Explanation

Solution

At constant 8.31×107dynecmK−1mol−18.31 \times 10^{7}dynecmK^{- 1}mol^{- 1}

8.31JK−1mol−18.31JK^{- 1}mol^{- 1}; 8.31atm.K−1mol−18.31atm.K^{- 1}mol^{- 1}