Question

If 2$x^2 + 2 <20$;, which of the following cannot be the value of $x$?

• A. 0
• B. 1
• C. 2
• D. 3

Answer 1

Answer: (D)

3

Answer 2

To solve the inequality 2$x^2 + 2 <20$,we can simplify it:
Subtract 2 from both sides:
⇒$2x^2 < 18$
Divide by 2:
⇒$x^2 < 9$
Taking the square root of both sides gives:
⇒$-3<x<3$
Now, let's evaluate the options to find which cannot be the value of
A. $x=0$:This is within the range $-3<x<3$
B. $x=1$:This is within the range$-3<1<3$
C. $x=2$:This is within the range$-3<2<3$
D.$x=3$:This is within the range $3$ is not less than 3
The value of $x$ that cannot satisfy the inequality.
So the correct option is (D):3