Question

If 11 A.M.'s are inserted between 28 and 10, then number of integral A.M's is-

• A. 5
• B. 6
• C. 7
• D. 8

Answer 1

Answer: (A)

5

Answer 2

d = $\frac{10 - 28}{11 + 1}$= $\frac{- 18}{12}$= $\frac{- 3}{2}$

A_m = 28 + (m) × $\frac{- 3}{2}$

Ž m must be even