Question

If 100mL of 1N ${{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}$ is mixed with 100mL of 1M NaOH solution. The resulting solution will be:
(A) Highly acidic
(B) Neutral
(C) Highly basic
(D) Slightly acidic

Answer 1

The sulphuric acid is a strong acid and NaOH is a strong base.
- Normality of a solution can be referred to as the number of gram equivalents of the solute present in solution multiplied with the molarity of the solution.

Complete step by step answer:
- So in the question, it is asked, we have to comment on the resulting solution formed, if 100 mL of ${{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}$ which of 1N is mixed with 1M NaOH solution. So to solve this problem we should have a basic idea of the solution, the components in them, the parameters by which the concentration of the solution can be represented and the relation between them.
- Solution is a homogeneous mixture formed by the mixing of two or more substances; the solution consists of two components: solute and a solvent. The solute is the substance that gets mixed uniformed in a dissolving medium and the solvent is the medium in which the solute is dissolved in.
- Now we have to discuss how to represent the concentration of the solution in accordance with the substances added. We generally use concentration parameters like normality, molarity to represent the concentration.
- The normality and molarity terms are related to each other, since we could calculate normality of the solution if the number of gram equivalents and the molarity is given.
$\text{Normality = n }\\!\\!\times\\!\\!\text{ Molarity}$, where n is the number of gram equivalence
- And it should be noted that if for the substance n value is, then the molarity and normality of the solution will be equal.
- The n value of a base can be defined as the number of $O{{H}^{-}}$ ions that a base can donate and for acid it is the number of protons i.e. ${{H}^{+}}$ ions that can be furnished in the solution.
- Now let’s solve the question given here, so here 1 N ${{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}$ and 1M NaOH solution is mixed together.
As the n factor of NaOH is 1, molarity is equal to normality.
To make up the solution an equal amount of acid and base is added. If we compare the nature of the substance added, then NaOH is a strong base and ${{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}$ is a strong acid so the solution produced will be neutral in nature. The correct option is option “B” .

Note: Strong acids and bases are those chemicals which will ionize completely in the solution.
- If a strong acid and weak base is mixed together then the salt formed will be acidic in nature and if weak acid and strong base is added then a basic salt is formed.