Question

If 100j of heat a supplied to 3kg mass to change temp by 30 degree celsius. Find that supplied

Answer 1

The specific heat capacity of the substance is $\frac{10}{9} \, \text{J/}(\text{kg} \, ^\circ\text{C})$ or approximately $1.11 \, \text{J/}(\text{kg} \, ^\circ\text{C})$.

Answer 2

The heat supplied ($Q$) to a mass ($m$) to change its temperature by $\Delta T$ is given by $Q = m \times c \times \Delta T$, where $c$ is the specific heat capacity. Rearranging the formula to find $c$, we get $c = Q / (m \times \Delta T)$. Substituting the given values $Q = 100 \, \text{J}$, $m = 3 \, \text{kg}$, and $\Delta T = 30 \, ^\circ\text{C}$, we calculate $c = 100 / (3 \times 30) = 100 / 90 = 10/9 \, \text{J/}(\text{kg} \, ^\circ\text{C})$.