Question

If $?=10^{-10}m$ changes to $?'=0.5 \times 10^{-10}m,$ find energy difference $(?E)$ given to the particle

• A. $?E$ is equal to $\bigg (\frac {1}{4}\bigg )^{th}$ of initial energy
• B. $? E$ is equal to $\bigg (\frac {1}{2}\bigg )^{th}$ of initial energy
• C. $?E$ is equal to twice of initial energy
• D. $?E$ is equal to initial energy

Answer 1

Answer: (D)

$?E$ is equal to initial energy

Answer 2

$E_1= \frac {hc}{?_1} \, and \, E_2= \frac {hc}{?_2}$ Clearly, $?_1=2 ?_2 \Rightarrow ?_2=\frac {?_1}{2}$ $\therefore E_2-E_1= \frac {hc}{?_2}- \frac {hc}{?_1}$ $\Rightarrow ? E= \frac {2hc}{?_1}- \frac {hc}{?_1}= \frac {hc}{?_1}$ $\Rightarrow ?E=E_1$