Question
Question: If \((1 + x)^{n} = C_{0} + C_{1}x + C_{2}x^{2} + ....... + C_{n}x^{n}\), then the value of \(C_{0} +...
If (1+x)n=C0+C1x+C2x2+.......+Cnxn, then the value of C0+2C1+3C2+......(n+1)Cn will be
A
(n+2)2n−1
B
(n+1)2n
C
(n+1)2n−1
D
(n+2)2n
Answer
(n+2)2n−1
Explanation
Solution
Sol. Trick: Put n=1 the expansion is equivalent to 1⥂C0+2.1C1=1+2=3.
Which is given by option (1) = (n+2)2n−1 =(1+2)20=3