Question
Mathematics Question on Trigonometric Functions
If 1+sinθ+sin2θ+............. $to \infty=4+2\sqrt{3},0
A
6π
B
3π
C
3πor6π
D
3πor32π
Answer
3πor32π
Explanation
Solution
1+sinθ+sin2θ+............=4+23
If 1+sinθ+sin2θ+............. $to \infty=4+2\sqrt{3},0
6π
3π
3πor6π
3πor32π
3πor32π
1+sinθ+sin2θ+............=4+23