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Question: If 1 g of solute (molar mass = \(50gmol^{- 1}\)) is dissolved in 50 g of solvent and the elevation i...

If 1 g of solute (molar mass = 50gmol150gmol^{- 1}) is dissolved in 50 g of solvent and the elevation in boiling point is 1 K. the molar boiling constant of the solvent is

A

2

B

3

C

2.52.5

D

5

Answer

2.52.5

Explanation

Solution

ΔTb=Kb×m\Delta T_{b} = K_{b} \times m

Or Kb=ΔTbm=1150×100050=52=2.5K_{b} = \frac{\Delta T_{b}}{m} = \frac{1}{\frac{1}{50} \times \frac{1000}{50}} = \frac{5}{2} = 2.5