Question
Question: If \(1+\cot \theta =\cos ec\theta \), then the general value of \(\theta \) is \(1)\text{ }n\pi +\...
If 1+cotθ=cosecθ, then the general value of θ is
1) nπ+2π
3) 2nπ−2π
3) 2nπ+2π
4) None of these
Solution
In this question we have been given with a trigonometric expression for which we have to find the general value of θ. We will solve this question by simplifying the terms in the expression and then rearranging the terms to get the expression in the form of sinθ and cosθ. We will then use the double angle formula to further simplify the expression and get the required solution.
Complete step-by-step solution:
We have the expression given to us as:
⇒1+cotθ=cosecθ
Now we know that cotθ=sinθcosθ and cosecθ=sinθ1 therefore, on substituting, we get:
⇒1+sinθcosθ=sinθ1
On taking the lowest common multiple on the left-hand side of the expression, we get:
⇒sinθsinθ+cosθ=sinθ1
Now since the denominator on both the sides is same, we cancel them and write it as:
⇒sinθ+cosθ=1
On squaring both the sides, we get:
⇒(sinθ+cosθ)2=12
On expanding the terms, we get:\
⇒sin2θ+2sinθcosθ+cos2θ=12
Now we know the identity that sin2θ+cos2θ=1 therefore, we can write:
⇒1+2sinθcosθ=1
Now we know the formula sin2θ=2sinθcosθ therefore, we get:
⇒sin2θ=0
Now we know the general solution that when sin2θ=0, we have the value of θ as:
⇒θ=2nπ+2π, which is the required value.
Therefore, the correct option is (3).
Note: To simplify any given equation, it is good practice to convert all the identities into sinθ and cosθ for simplifying. If there is nothing to simplify, then only you should use the double angle formulas to expand the given equation. The various trigonometric identities and formulae should be remembered while doing these types of sums.