Question

If α = 0.98 and current through emitter i_e = 20 mA, the value of β is

• A. 4.9
• B. 49
• C. 96
• D. 9.6

Answer 1

Answer: (B)

49

Answer 2

$\beta = \frac{\alpha}{1 - \alpha} = \frac{0.98}{1 - 0.98}$=49.