Question

If 0.224 L of H2 gas is formed at the cathode, the volume of O2 gas formed at the anode under identical conditions, is

• A. 0.224 L
• B. 0.448 L
• C. 0.112 L
• D. 1.12 L

Answer 1

Answer: (C)

0.112 L

Answer 2

equivalence of H2 = equivalence of O $\frac { 0.224 } { 22.4 }$ ´ 2

= $\frac { \text { volume of } \mathrm { O } _ { 2 } } { 22.4 }$ ´ 4 0.112 litre = volume of O2.